- How much work is done on a 300 Newton suitcase to lift it 0.50 meter?
- How much energy does it take to lift 1kg 1m?
- How much does a 1 hp motor weight?
- How much weight can an electric motor lift?
- How much energy does it take to lift 1 ton?
- How much weight can a 1/2 hp motor lift?
- Which two quantities can be expressed with the same units?
- What is the average power required to lift a 100 kg mass to a height of 50m in 50 seconds?
- How much power is required to lift a body of 50kg?
- How many watts does it take to lift 1kg?
- How much does a 100 hp motor weight?
- What is the rate at which work is done in lifting a 35?
- What is the average power required to lift?
- What power is expended in lifting a 50kg weight to a height of 20m in one minute?
- How long will it take a 2.5 KW motor to lift a 80 kg block 30m high?
- How do you calculate the lifting capacity of a motor?
- How much force is needed to lift the 10Kg weight?
- How much weight can a 12V DC motor lift?
- How do we calculate torque?
- Which quantity is a measure of the rate at which work is done?

## How much work is done on a 300 Newton suitcase to lift it 0.50 meter?

1 Answer.

Work done is force multiplied by distance, Hence work done is 300×0.50=150 joules..

## How much energy does it take to lift 1kg 1m?

On earth it takes about 10 Newton-meters (N-m) of energy to raise a 1 kilogram mass to a height of 1 meter. Since 1 N-m equals 1 Joule, that’s 10 Joules. If it takes 1 second to lift the weight 1 meter, than you have converted 10 Joules of energy to potential energy in one second. That’s 10 Watts of power.

## How much does a 1 hp motor weight?

Most engines use horsepower to describe how much work they can do in a given amount of time. The constant 1 horsepower equals 550 foot-pounds per second. In other words, 1 horsepower is the amount of work required to move a load of 550 pounds over 1 foot, in 1 second.

## How much weight can an electric motor lift?

This means with 1 hp, you can lift about 550 lbs (250 kg) at a rate of 1 ft/sec, 1100 lbs at a rate of 0.5 ft/sec, 225 lb at a rate of 2 ft/sec, 1 lb at a rate of 550 ft/sec, and so on. It depends not only on the weight, but the rate (speed) at which you want to lift that weight.

## How much energy does it take to lift 1 ton?

Assuming you mean a tonne – ie a metric tonne, 1000kg – the energy required to lift one tonne to a height of one meter is given by the equation ‘mgh’ – mass times the acceleration due to gravity times the height, so that’s 1000 * 9.8 * 1, or 9,800 Joules.

## How much weight can a 1/2 hp motor lift?

To find the weight each opener can lift simply divide 550 lbs by the manufacturer HP rating and then multiply by (2/3). For example, a 1/2 horsepower garage door opener should be able to lift 275 pounds while a 1 HP opener can lift 550 pounds.

## Which two quantities can be expressed with the same units?

Thus, we can conclude that impulse and momentum are the two quantities which are measured in the same units.

## What is the average power required to lift a 100 kg mass to a height of 50m in 50 seconds?

The average power required to lift a 100 kg mass through a height of 50 metres in approximately 50 seconds would be [SCRA 1994; MH CET 2000] A) 50 J/s. B) 5000 J/s.

## How much power is required to lift a body of 50kg?

So, the body will posses 4900 joules of energy. It is the required solution.

## How many watts does it take to lift 1kg?

10 WattsIf you can keep lifting a 1 kg weight to a height of 1 meter every second, weight after weight after weight, then you will be steadily producing 10 Watts of power.

## How much does a 100 hp motor weight?

1296 lbs.100HP BALDOR 1785RPM 405T TEFC 3PH MOTOR ECP4400T-4Catalog Number:ECP4400T-4 – FREE Ground Shipping in USADescription:100HP,1785RPM,405T,TEFC,3PH,60HZ,CHEM DUTY,PREMIUMShip Weight:1296 lbs.

## What is the rate at which work is done in lifting a 35?

Explanation: The rate at which work is done is also the power dissipated in lifting the object at that constant speed. Therefore, the the rate at which work is done in lifting the object vertically at a constant speed of 5 m/s is 1,700 W.

## What is the average power required to lift?

Therefore, the power required is 980J/s. The correct option is D. Note: Power which is the product of force and velocity is called instantaneous velocity power, and average power is force times average velocity.

## What power is expended in lifting a 50kg weight to a height of 20m in one minute?

Answer: The power expended is equal to 163.33 Watts or 163.33 J/s.

## How long will it take a 2.5 KW motor to lift a 80 kg block 30m high?

Option (A) is correct. Motor will take 9.4 s to lift block. Work done by motor to lift block is equal to change in gravitational potential energy of block.

## How do you calculate the lifting capacity of a motor?

Force needed to hold 100 kg against gravity = 100*9.8, rounding it up to 1000N. Let’s say the machine lifts it up at a rate of 1 meter per second. So power needed would be 1000 x 1 = 1kW.

## How much force is needed to lift the 10Kg weight?

5 Kg forceHow much force is needed to lift the 10Kg weight? The correct answer is (B) 5 Kg. In a double-pulley system, the force is equal to the weight divided by two. It will require a 5 Kg force to lift a 10Kg weight.

## How much weight can a 12V DC motor lift?

Weight: 100 gm(Approx.) RPM: 100 Operating Voltage: 12V DC Gearbox: Attached Plastic (spur)Gearbox Shaft diameter: 6mm Shaft Length: 21 mm Torque: 1.2 Kg-cm. No-load current = 60 mA(Max) Load current = 300 mA(Max).

## How do we calculate torque?

A practical way to calculate the magnitude of the torque is to first determine the lever arm and then multiply it times the applied force. The lever arm is the perpendicular distance from the axis of rotation to the line of action of the force. and the magnitude of the torque is τ = N m.

## Which quantity is a measure of the rate at which work is done?

powerpower: A measure of the rate of doing work or transferring energy. watt: In the International System of Units, the derived unit of power; the power of a system in which one joule of energy is transferred per second.