- Is a Tesla motor AC or DC?
- How much torque is required to move a car?
- How much weight can a NEMA 23 lift?
- What is the rate at which work is done in lifting a 35?
- How long will it take a 2.5 KW motor to lift a 80 kg block 30 m high?
- How much force is needed to lift the 10Kg weight?
- How much power is required to lift a body of 50kg?
- How much does a 50 hp electric motor weight?
- What is the formula to calculate torque?
- How do you calculate the lifting capacity of a motor?
- How much does a 100 hp motor weight?
- How much energy does it take to lift 1kg 1m?
- How much does a 300 hp electric motor weight?
- How do you calculate torque needed?
- What force is required to lift the 100 pound weight?
- How much torque is required to lift a weight?
- How much force is needed to lift a 25kg mass?
- How many watts does it take to lift 1kg?
- How do you measure the maximum weight that a DC motor can move?
- How do you calculate RPM on a DC motor?
- How much weight can a 12V DC motor lift?

## Is a Tesla motor AC or DC?

Tesla, for example, uses alternating current (AC) induction motors in the Model S but uses permanent-magnet direct current (DC) motors in its Model 3..

## How much torque is required to move a car?

Overall transmission (and power-train) efficiency of the modern electric vehicles is within 59 .. 62 %. The answer to your question is 43.2 Nm of Torque required that can be obtained with the transmission ratio value of 15.

## How much weight can a NEMA 23 lift?

2. Weight, and gearing play a big role. Nema 23’s can probably move 1000lbs. The question is how fast do you want to move that weight.

## What is the rate at which work is done in lifting a 35?

Explanation: The rate at which work is done is also the power dissipated in lifting the object at that constant speed. Therefore, the the rate at which work is done in lifting the object vertically at a constant speed of 5 m/s is 1,700 W.

## How long will it take a 2.5 KW motor to lift a 80 kg block 30 m high?

Motor will take 9.4 s to lift block. Work done by motor to lift block is equal to change in gravitational potential energy of block.

## How much force is needed to lift the 10Kg weight?

5 Kg forceHow much force is needed to lift the 10Kg weight? The correct answer is (B) 5 Kg. In a double-pulley system, the force is equal to the weight divided by two. It will require a 5 Kg force to lift a 10Kg weight.

## How much power is required to lift a body of 50kg?

So, the body will posses 4900 joules of energy. It is the required solution.

## How much does a 50 hp electric motor weight?

597 lbsLEESON 50 HP Electric AC Motor – 3 Phase – 1780 RPM – TEFC – Rigid Mount – 320 Frame – Wattsaver Equipped with LEESON’s Spike-Resistant Insulation System….Additional information.BrandLeesonWeight597 lbsItem TypeElectric MotorHP50RPM17802 more rows

## What is the formula to calculate torque?

A practical way to calculate the magnitude of the torque is to first determine the lever arm and then multiply it times the applied force. The lever arm is the perpendicular distance from the axis of rotation to the line of action of the force. and the magnitude of the torque is τ = N m.

## How do you calculate the lifting capacity of a motor?

Force needed to hold 100 kg against gravity = 100*9.8, rounding it up to 1000N. Let’s say the machine lifts it up at a rate of 1 meter per second. So power needed would be 1000 x 1 = 1kW.

## How much does a 100 hp motor weight?

1296 lbs.100HP BALDOR 1785RPM 405T TEFC 3PH MOTOR ECP4400T-4Catalog Number:ECP4400T-4 – FREE Ground Shipping in USADescription:100HP,1785RPM,405T,TEFC,3PH,60HZ,CHEM DUTY,PREMIUMShip Weight:1296 lbs.

## How much energy does it take to lift 1kg 1m?

On earth it takes about 10 Newton-meters (N-m) of energy to raise a 1 kilogram mass to a height of 1 meter. Since 1 N-m equals 1 Joule, that’s 10 Joules. If it takes 1 second to lift the weight 1 meter, than you have converted 10 Joules of energy to potential energy in one second. That’s 10 Watts of power.

## How much does a 300 hp electric motor weight?

3135 lbs.300HP BALDOR 1785RPM 449T TEFC 3PH MOTOR ECP44304TR-4Catalog Number:ECP44304TR-4 – FREE Ground Shipping in USADescription:300HP,1785RPM,449T,TEFC,3PH,60HZ,CHEM DUTY,PREMIUMShip Weight:3135 lbs.

## How do you calculate torque needed?

The required torque is calculated by multiplying the sum of load torque and acceleration torque by the safety factor. When the required torque for the motor varies over time, determine if the motor can be used by calculating the effective load torque.

## What force is required to lift the 100 pound weight?

So, as in the picture below, you pull the rope down to lift the weight up. If you want to lift something that weighs 100kg, you have to pull down with a force equivalent to 100kg, which is 1000N (newtons).

## How much torque is required to lift a weight?

To calculate load torque, multiply the force (F) by the distance away from the rotational axis, which is the radius of the pulley (r). If the mass of the load (blue box) is 20 Newtons, and the radius of the pulley is 5 cm away, then the required torque for the application is 20 N x 0.05 m = 1 Nm.

## How much force is needed to lift a 25kg mass?

It is F = ma =mg =25kg•9.81m/s^2 = 245.25N. This is because you have to use a force equal to its weight at least( in Newton) to lift it up.

## How many watts does it take to lift 1kg?

10 WattsIf you can keep lifting a 1 kg weight to a height of 1 meter every second, weight after weight after weight, then you will be steadily producing 10 Watts of power.

## How do you measure the maximum weight that a DC motor can move?

The maximum power will be produced at the maximum rpm of the motor. Multiply the torque of the motor time the ratio of gear or belt reduction to drive the wheel axle, then divide by the radius of the wheel. Can we assume you will use wheels? The torque will tell you how much weight can be moved by the motor.

## How do you calculate RPM on a DC motor?

One crucial measurement is revolutions per minute, or RPM, which describes the speed of a motor….For a 60 Hz system with four poles, the calculations to determine RPM would be:(Hz x 60 x 2) / number of poles = no-load RPM.(60 x 60 x 2) / 4.7,200 / 4 = 1,800 RPM.

## How much weight can a 12V DC motor lift?

Weight: 100 gm(Approx.) RPM: 100 Operating Voltage: 12V DC Gearbox: Attached Plastic (spur)Gearbox Shaft diameter: 6mm Shaft Length: 21 mm Torque: 1.2 Kg-cm. No-load current = 60 mA(Max) Load current = 300 mA(Max).